A stick is tied to the floor of the water tank with a strin…

Physics Fluid Mechanics Mix MCQ (Single Correct)

A stick is tied to the floor of the water tank with a string as shown. The length of stick is 2 m and its area of cross-section is 10 –3 m 2 . If specific gravity of stick is 0.25 and g = 10 m/s 2 , then –

Tension in the string is 5 N

Buoyancy force acting on stick is 10 N

Length of stick immersed in water is 1 m

Tension in the string is zero

Text Solution

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The correct answer is:

CHECK THE SOLUTION.

(a, b, c)

If A is area of cross-section then,

ρ W A λ g = T + mg .... (1)

where λ is the length of stick immersed in water.

Now, taking torque

ρ W λ Ag × cos θ = mg × cos θ

or ρ W λ 2 = ρ S L 2 .... (2)

Solve equation (1) and equation (2)

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